Lead Nitrate and Potassium Iodide Reaction Experiment | Class 10 Science Chemical Reactions and Equations
The lead nitrate and potassium iodide reaction is an important Class 10 Science experiment prescribed for RBSE practical work and based on Chapter 1 Chemical reactions and equation of NCERT.
In this experiment,
two colourless solutions lead nitrate and potassium iodide react to form a
bright yellow precipitate of lead iodide demonstrating a double displacement reaction
and precipitation reaction.
This experiment
helps students understand how new substances are formed during a chemical
reaction.
Experiment No - 2- Lead Nitrate and Potassium Iodide Reaction
Objective
To study the
reaction between lead nitrate solution and potassium iodide solution
Materials/ Apparatus
1. Lead nitrate solution
2. Potassium iodide solution
3. Two test tubes
4. Dropper
5. Test tube stand
Theory
When an aqueous
solution of lead nitrate reacts with an aqueous solution of potassium iodide, a
yellow insoluble solid called lead iodide is formed. This reaction is an example
of a double displacement reaction and also a precipitation reaction because an insoluble
solid is produced.
Procedure
You should follow
these steps to perform this experiment:
1. Take about 5 mL of lead nitrate solution in a test
tube.
2. Take about 5 mL of potassium iodide solution in
another test tube.
3. Add potassium iodide solution slowly into the test
tube containing lead nitrate solution.
4. Shake the test tube gently and observe the changes.
Observation
·
A
bright yellow coloured precipitate is formed immediately.
·
The
solution turns cloudy due the formation of lead iodide.
Chemical Equation
Pb(NO3)2(aq) + 2KI(aq)
→PbI2(s) + 2KNO3(aq)
Result
When lead nitrate
reacts with potassium iodide solution, a yellow precipitate of lead iodide is
formed. This confirms a double displacement reaction. The reaction is also
known as precipitate reaction.
Precautions
·
Use
clean test tubes
·
Add
the solution slowly
·
Do
not touch the chemical directly
·
Wash
hands after the experiment.
Viva Questions
Q1. What is the
colour of precipitate formed in this reaction?
Q2. Name the precipitate
formed.
Q3. What type of
reaction involved in the experiment?
Q4. Why is this
called a precipitate reaction?
Q5. Write the
balanced chemical equation?
Viva Answers
1. The precipitate formed is yellow in colour.
2. The precipitate is lead iodide.
3. It is a double displacement reaction.
4. Because an insoluble solid (precipitate) is formed
during the reaction.
5. Pb(NO3)2(aq) + 2KI(aq) →PbI2(s) + 2KNO3(aq)
Related Topics
1. Burning of Magnesium Ribbon Experiment
2. Zinc and Hydrochloric Acid Reaction Experiment

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